[go: up one dir, main page]

login

Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 61st year, we have over 378,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).

A081168
Differences of Beatty sequence for square root of 10.
4
3, 3, 3, 3, 3, 3, 4, 3, 3, 3, 3, 3, 4, 3, 3, 3, 3, 3, 4, 3, 3, 3, 3, 3, 4, 3, 3, 3, 3, 3, 4, 3, 3, 3, 3, 3, 4, 3, 3, 3, 3, 3, 3, 4, 3, 3, 3, 3, 3, 4, 3, 3, 3, 3, 3, 4, 3, 3, 3, 3, 3, 4, 3, 3, 3, 3, 3, 4, 3, 3, 3, 3, 3, 4, 3, 3, 3, 3, 3, 3, 4, 3, 3, 3, 3, 3, 4, 3, 3, 3, 3, 3, 4, 3, 3, 3, 3, 3, 4, 3, 3, 3, 3, 3, 4
OFFSET
0,1
COMMENTS
Let S(0) = 3; obtain S(k) from S(k-1) by applying the morphism 3 -> 333334, 4 -> 3333334; sequence is S(0), S(1), S(2), ...
More generally, for a(n,m) = floor((n+1)*sqrt(m^2+ 1)) - floor(n*sqrt(m^2+1)) start with m and apply the morphism: m -> m^(2m-1), m+1; m+1 -> m^(2m), m+1.
LINKS
FORMULA
a(n) = floor((n+1)*sqrt(10)) - floor(n*sqrt(10)).
MATHEMATICA
Differences[Floor[Sqrt[10]*Range[0, 120]]] (* G. C. Greubel, Jan 15 2024 *)
PROG
(PARI) a(n)=floor((n+1)*sqrt(10))-floor(n*sqrt(10))
(Magma)
A081168:= func< n | Floor((n+1)*Sqrt(10)) - Floor(n*Sqrt(10)) >;
[A081168(n): n in [0..120]]; // G. C. Greubel, Jan 15 2024
(SageMath)
def A081168(n): return floor((n+1)*sqrt(10)) - floor(n*sqrt(10))
[A081168(n) for n in range(121)] # G. C. Greubel, Jan 15 2024
CROSSREFS
KEYWORD
nonn
AUTHOR
Benoit Cloitre, Apr 16 2003
STATUS
approved