[go: up one dir, main page]

DEV Community

Abhishek Chaudhary
Abhishek Chaudhary

Posted on

Replace Words

In English, we have a concept called root, which can be followed by some other word to form another longer word - let's call this word successor. For example, when the root "an" is followed by the successor word "other", we can form a new word "another".

Given a dictionary consisting of many roots and a sentence consisting of words separated by spaces, replace all the successors in the sentence with the root forming it. If a successor can be replaced by more than one root, replace it with the root that has the shortest length.

Return the sentence after the replacement.

Example 1:

Input: dictionary = ["cat","bat","rat"], sentence = "the cattle was rattled by the battery"
Output: "the cat was rat by the bat"

Example 2:

Input: dictionary = ["a","b","c"], sentence = "aadsfasf absbs bbab cadsfafs"
Output: "a a b c"

Constraints:

  • 1 <= dictionary.length <= 1000
  • 1 <= dictionary[i].length <= 100
  • dictionary[i] consists of only lower-case letters.
  • 1 <= sentence.length <= 106
  • sentence consists of only lower-case letters and spaces.
  • The number of words in sentence is in the range [1, 1000]
  • The length of each word in sentence is in the range [1, 1000]
  • Every two consecutive words in sentence will be separated by exactly one space.
  • sentence does not have leading or trailing spaces.

SOLUTION:

class Solution:
    def replaceWords(self, dictionary: List[str], sentence: str) -> str:
        dictionary = set(dictionary)
        lens = sorted([len(w) for w in dictionary])
        words = sentence.split()
        op = []
        for w in words:
            found = False
            for l in lens:
                if w[:l] in dictionary:
                    op.append(w[:l])
                    found = True
                    break
            if not found:
                op.append(w)
        return " ".join(op)
Enter fullscreen mode Exit fullscreen mode

Top comments (0)