Binary Prefix Divisible By 5

You are given a binary array nums (0-indexed).

We define xi as the number whose binary representation is the subarray nums[0..i] (from most-significant-bit to least-significant-bit).

• For example, if nums = [1,0,1], then x0 = 1, x1 = 2, and x2 = 5.

Return an array of booleans answer where answer[i] is true if xi is divisible by 5.

Example 1:

Input: nums = [0,1,1]
Output: [true,false,false]
Explanation: The input numbers in binary are 0, 01, 011; which are 0, 1, and 3 in base-10.
Only the first number is divisible by 5, so answer[0] is true.

Example 2:

Input: nums = [1,1,1]
Output: [false,false,false]

Constraints:

• 1 <= nums.length <= 105
• nums[i] is either 0 or 1.

SOLUTION:

class Solution:
    def prefixesDivBy5(self, nums: List[int]) -> List[bool]:
        val = 0
        op = []
        for num in nums:
            val = 2 * val + num
            if val % 5 == 0:
                op.append(True)
            else:
                op.append(False)
        return op