OFFSET
0,5
COMMENTS
Note that these partitions are located in the head of the last section of the set of partitions of n (see A135010). - Omar E. Pol, Nov 20 2009
Number of symmetric unimodal compositions of n+2 where the maximal part appears twice, see example. Also number of symmetric unimodal compositions of n where the maximal part appears an even number of times. - Joerg Arndt, Jun 11 2013
Number of partitions of n having parts of even multiplicity. These are the conjugates of the partitions from the definition. Example: a(8)=5 because we have [4,4],[3,3,1,1],[2,2,2,2],[2,2,1,1,1,1], and [1,1,1,1,1,1,1,1]. - Emeric Deutsch, Jan 27 2016
From Gus Wiseman, May 22 2021: (Start)
The Heinz numbers of the conjugate partitions described in Emeric Deutsch's comment above are given by A000290.
For n > 1, also the number of integer partitions of n-1 whose only odd part is the smallest. The Heinz numbers of these partitions are given by A341446. For example, the a(2) = 1 through a(14) = 15 partitions (empty columns shown as dots, A..D = 10..13) are:
1 . 3 . 5 . 7 . 9 . B . D
21 41 43 63 65 85
221 61 81 83 A3
421 441 A1 C1
2221 621 443 643
4221 641 661
22221 821 841
4421 A21
6221 4441
42221 6421
222221 8221
44221
62221
422221
2222221
Also the number of integer partitions of n whose greatest part is the sum of all the other parts. The Heinz numbers of these partitions are given by A344415. For example, the a(2) = 1 through a(12) = 11 partitions (empty columns not shown) are:
(11) (22) (33) (44) (55) (66)
(211) (321) (422) (532) (633)
(3111) (431) (541) (642)
(4211) (5221) (651)
(41111) (5311) (6222)
(52111) (6321)
(511111) (6411)
(62211)
(63111)
(621111)
(6111111)
Also the number of integer partitions of n of length n/2. The Heinz numbers of these partitions are given by A340387. For example, the a(2) = 1 through a(14) = 15 partitions (empty columns not shown) are:
(2) (22) (222) (2222) (22222) (222222) (2222222)
(31) (321) (3221) (32221) (322221) (3222221)
(411) (3311) (33211) (332211) (3322211)
(4211) (42211) (333111) (3332111)
(5111) (43111) (422211) (4222211)
(52111) (432111) (4322111)
(61111) (441111) (4331111)
(522111) (4421111)
(531111) (5222111)
(621111) (5321111)
(711111) (5411111)
(6221111)
(6311111)
(7211111)
(8111111)
(End)
REFERENCES
Mohammad K. Azarian, A Generalization of the Climbing Stairs Problem, Mathematics and Computer Education, Vol. 31, No. 1, pp. 24-28, Winter 1997. MathEduc Database (Zentralblatt MATH, 1997c.01891).
Mohammad K. Azarian, A Generalization of the Climbing Stairs Problem II, Missouri Journal of Mathematical Sciences, Vol. 16, No. 1, Winter 2004, pp. 12-17. Zentralblatt MATH, Zbl 1071.05501.
LINKS
Robert Price, Table of n, a(n) for n = 0..2001
FORMULA
G.f.: Product_{k even} 1/(1 - x^k).
Convolution with the number of partitions into distinct parts (A000009, which is also number of partitions into odd parts) gives the number of partitions (A000041). - Franklin T. Adams-Watters, Jan 06 2006
If n is even then a(n)=A000041(n/2) otherwise a(n)=0. - Omar E. Pol, Nov 20 2009
G.f.: 1 + x^2*(1 - G(0))/(1-x^2) where G(k) = 1 - 1/(1-x^(2*k+2))/(1-x^2/(x^2-1/G(k+1) )); (recursively defined continued fraction). - Sergei N. Gladkovskii, Jan 23 2013
G.f.: exp(Sum_{k>=1} x^(2*k)/(k*(1 - x^(2*k)))). - Ilya Gutkovskiy, Aug 13 2018
EXAMPLE
From Joerg Arndt, Jun 11 2013: (Start)
There are a(12)=11 symmetric unimodal compositions of 12+2=14 where the maximal part appears twice:
01: [ 1 1 1 1 1 2 2 1 1 1 1 1 ]
02: [ 1 1 1 1 3 3 1 1 1 1 ]
03: [ 1 1 1 4 4 1 1 1 ]
04: [ 1 1 2 3 3 2 1 1 ]
05: [ 1 1 5 5 1 1 ]
06: [ 1 2 4 4 2 1 ]
07: [ 1 6 6 1 ]
08: [ 2 2 3 3 2 2 ]
09: [ 2 5 5 2 ]
10: [ 3 4 4 3 ]
11: [ 7 7 ]
There are a(14)=15 symmetric unimodal compositions of 14 where the maximal part appears an even number of times:
01: [ 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ]
02: [ 1 1 1 1 1 2 2 1 1 1 1 1 ]
03: [ 1 1 1 1 3 3 1 1 1 1 ]
04: [ 1 1 1 2 2 2 2 1 1 1 ]
05: [ 1 1 1 4 4 1 1 1 ]
06: [ 1 1 2 3 3 2 1 1 ]
07: [ 1 1 5 5 1 1 ]
08: [ 1 2 2 2 2 2 2 1 ]
09: [ 1 2 4 4 2 1 ]
10: [ 1 3 3 3 3 1 ]
11: [ 1 6 6 1 ]
12: [ 2 2 3 3 2 2 ]
13: [ 2 5 5 2 ]
14: [ 3 4 4 3 ]
15: [ 7 7 ]
(End)
a(8)=5 because we have [8], [6,2], [4,4], [4,2,2], and [2,2,2,2]. - Emeric Deutsch, Jan 27 2016
From Gus Wiseman, May 22 2021: (Start)
The a(0) = 1 through a(12) = 11 partitions into even parts are the following (empty columns shown as dots, A = 10, C = 12). The Heinz numbers of these partitions are given by A066207.
() . (2) . (4) . (6) . (8) . (A) . (C)
(22) (42) (44) (64) (66)
(222) (62) (82) (84)
(422) (442) (A2)
(2222) (622) (444)
(4222) (642)
(22222) (822)
(4422)
(6222)
(42222)
(222222)
(End)
MAPLE
ZL:= [S, {C = Cycle(B), S = Set(C), E = Set(B), B = Prod(Z, Z)}, unlabelled]: seq(combstruct[count](ZL, size=n), n=0..69); # Zerinvary Lajos, Mar 26 2008
g := 1/mul(1-x^(2*k), k = 1 .. 100): gser := series(g, x = 0, 80): seq(coeff(gser, x, n), n = 0 .. 78); # Emeric Deutsch, Jan 27 2016
# Using the function EULER from Transforms (see link at the bottom of the page).
[1, op(EULER([0, 1, seq(irem(n, 2), n=0..66)]))]; # Peter Luschny, Aug 19 2020
# next Maple program:
a:= n-> `if`(n::odd, 0, combinat[numbpart](n/2)):
seq(a(n), n=0..84); # Alois P. Heinz, Jun 22 2021
MATHEMATICA
nmax = 50; s = Range[2, nmax, 2];
Table[Count[IntegerPartitions@n, x_ /; SubsetQ[s, x]], {n, 0, nmax}] (* Robert Price, Aug 05 2020 *)
PROG
(Python)
from sympy import npartitions
def A035363(n): return 0 if n&1 else npartitions(n>>1) # Chai Wah Wu, Sep 23 2023
CROSSREFS
Bisection (even part) gives the partition numbers A000041.
Note: A-numbers of ranking sequences are in parentheses below.
The version for parts divisible by 3 instead of 2 is A035377.
The strict case is A035457.
The Heinz numbers of these partitions are given by A066207.
The ordered version (compositions) is A077957 prepended by (1,0).
This is column k = 2 of A168021.
The multiplicative version (factorizations) is A340785.
The following count partitions of even length:
KEYWORD
nonn,easy
AUTHOR
STATUS
approved