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Revision History for A323639 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
a(n) = 3*(10^n - 4)/9.
(history; published version)
#34 by Harvey P. Dale at Sat Jan 09 12:50:04 EST 2021
STATUS

editing

approved

#33 by Harvey P. Dale at Sat Jan 09 12:50:00 EST 2021
COMMENTS

Conjecture: satisfies a linear recurrence having signature (11, -10). - Harvey P. Dale, Jan 09 2021

MATHEMATICA

Table[(10^n-4)/3, {n, 0, 20}] (* _or *) LinearRecurrence[{11, -10}, {-1, 2}, 21] (* _Harvey P. Dale_, Jan 09 2021 *)

STATUS

approved

editing

#32 by Harvey P. Dale at Sat Jan 09 12:49:15 EST 2021
STATUS

editing

approved

#31 by Harvey P. Dale at Sat Jan 09 12:49:12 EST 2021
COMMENTS

Conjecture: satisfies a linear recurrence having signature (11, -10). - Harvey P. Dale, Jan 09 2021

MATHEMATICA

Table[(10^n-4)/3, {n, 0, 20}] (* Harvey P. Dale, Jan 09 2021 *)

STATUS

approved

editing

#30 by Michel Marcus at Sun Sep 01 02:41:01 EDT 2019
STATUS

reviewed

approved

#29 by Joerg Arndt at Sun Sep 01 01:44:24 EDT 2019
STATUS

proposed

reviewed

#28 by Seiichi Manyama at Sat Aug 31 05:24:08 EDT 2019
STATUS

editing

proposed

#27 by Seiichi Manyama at Sat Aug 31 05:22:59 EDT 2019
FORMULA

a(2*n) = A198971(n-1) * A073555(n+1) * A198971(n-1) for n > 0.

EXAMPLE

4 * 8 * 4 = 32.

49 * 68 * 49 = 3332.

499 * 668 * 499 = 333332.

4999 * 6668 * 4999 = 33333332.

49999 * 66668 * 49999 = 3333333332.

#26 by Seiichi Manyama at Sat Aug 31 05:18:56 EDT 2019
FORMULA

a(2*n) = A198971(n-1) * A073555(n+1) for n > 0.

#25 by Seiichi Manyama at Sat Aug 31 05:17:42 EDT 2019
EXAMPLE

(-1) * 1 = -1.