[go: up one dir, main page]

login

Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 61st year, we have over 378,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).

Revision History for A283330 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
a(n) = (1 + Sum_{j=1..K-1} a(n-j) + a(n-1)*a(n-K+1))/a(n-K) with a(1),...,a(K)=1, where K=5.
(history; published version)
#39 by Joerg Arndt at Fri Nov 06 10:38:01 EST 2020
STATUS

reviewed

approved

#38 by Michel Marcus at Fri Nov 06 09:42:10 EST 2020
STATUS

proposed

reviewed

#37 by Kevin Ryde at Fri Nov 06 03:52:49 EST 2020
STATUS

editing

proposed

#36 by Kevin Ryde at Fri Nov 06 03:52:00 EST 2020
LINKS

<a href="/index/Rec#order_12">Index entries for linear recurrences with constant coefficients</a>, signature (0,0,0,153,0,0,0,-153,0,0,0,1).

FORMULA

Conjectures from _From _Colin Barker_, Nov 03 2020: (Start)

a(n) = 153*a(n-4) - 153*a(n-8) + a(n-12) for n>1112.

STATUS

proposed

editing

Discussion
Fri Nov 06
03:52
Kevin Ryde: Yes to this gf.  Recurrence n>12 (yes?).
#35 by Colin Barker at Tue Nov 03 09:14:04 EST 2020
STATUS

editing

proposed

#34 by Colin Barker at Tue Nov 03 09:13:18 EST 2020
FORMULA

Conjectures from Colin Barker, Nov 03 2020: (Start)

G.f.: x*(1 + x + x^2 + x^3 - 152*x^4 - 147*x^5 - 137*x^6 - 112*x^7 + 106*x^8 + 41*x^9 + 16*x^10 + 6*x^11) / ((1 - x)*(1 + x)*(1 + x^2)*(1 - 152*x^4 + x^8)).

a(n) = 153*a(n-4) - 153*a(n-8) + a(n-12) for n>11.

(End)

STATUS

proposed

editing

#33 by Jean-François Alcover at Tue Nov 03 07:38:40 EST 2020
STATUS

editing

proposed

#32 by Jean-François Alcover at Tue Nov 03 07:38:31 EST 2020
MATHEMATICA

a[n_] := a[n] = If[n <= 5, 1, SwitchWith[{m = If[Mod[n, 4], == 2, 8, 3]}, m a[n-1] - a[n-2] - 1]];

0, 3 a[n - 1] - a[n - 2] - 1,

1, 3 a[n - 1] - a[n - 2] - 1,

2, 8 a[n - 1] - a[n - 2] - 1,

3, 3 a[n - 1] - a[n - 2] - 1]];

STATUS

proposed

editing

#31 by Jean-François Alcover at Tue Nov 03 07:32:00 EST 2020
STATUS

editing

proposed

#30 by Jean-François Alcover at Tue Nov 03 07:31:43 EST 2020
MATHEMATICA

a[n_] := a[n] = If[n <= 5, 1, Switch[Mod[n, 4],

0, 3 a[n - 1] - a[n - 2] - 1,

1, 3 a[n - 1] - a[n - 2] - 1,

2, 8 a[n - 1] - a[n - 2] - 1,

3, 3 a[n - 1] - a[n - 2] - 1]];

Array[a, 30] (* Jean-François Alcover, Nov 03 2020 *)

STATUS

approved

editing