53941300 has 72 divisors (see below), whose sum is σ = 134741376. Its totient is φ = 18360960.

The previous prime is 53941273. The next prime is 53941309. The reversal of 53941300 is 314935.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53941309) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 183954 + ... + 184246.

It is an arithmetic number, because the mean of its divisors is an integer number (1871408).

Almost surely, 2^53941300 is an apocalyptic number.

53941300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 53941300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (67370688).

53941300 is an abundant number, since it is smaller than the sum of its proper divisors (80800076).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53941300 is a wasteful number, since it uses less digits than its factorization.

53941300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 577 (or 570 counting only the distinct ones).

The product of its (nonzero) digits is 1620, while the sum is 25.

The square root of 53941300 is about 7344.4741132364. The cubic root of 53941300 is about 377.8393072278.

The spelling of 53941300 in words is "fifty-three million, nine hundred forty-one thousand, three hundred".