Base | Representation |
---|---|
bin | 1111011000101010… |
… | …1111101111000100 |
3 | 101122211100100112010 |
4 | 3312022233233010 |
5 | 31424240341400 |
6 | 1521452254220 |
7 | 204226344414 |
oct | 36612575704 |
9 | 11584310463 |
10 | 4130012100 |
11 | 182a314245 |
12 | 973171370 |
13 | 50a842856 |
14 | 2b2718644 |
15 | 1928a7450 |
hex | f62afbc4 |
4130012100 has 72 divisors (see below), whose sum is σ = 12012231168. Its totient is φ = 1095555200.
The previous prime is 4130012069. The next prime is 4130012129. The reversal of 4130012100 is 12100314.
It is a happy number.
It is a super-2 number, since 2×41300121002 = 34113999892292820000, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 21262 + ... + 93338.
It is an arithmetic number, because the mean of its divisors is an integer number (166836544).
Almost surely, 24130012100 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 4130012100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (6006115584).
4130012100 is an abundant number, since it is smaller than the sum of its proper divisors (7882219068).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4130012100 is a wasteful number, since it uses less digits than its factorization.
4130012100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 72285 (or 72278 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 12.
The square root of 4130012100 is about 64265.1701935037. The cubic root of 4130012100 is about 1604.4164569551.
Adding to 4130012100 its reverse (12100314), we get a palindrome (4142112414).
The spelling of 4130012100 in words is "four billion, one hundred thirty million, twelve thousand, one hundred".
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