Base | Representation |
---|---|
bin | 100111111100011… |
… | …0101101110101000 |
3 | 10110102000022020011 |
4 | 1033320311232220 |
5 | 10221104101300 |
6 | 340555141304 |
7 | 45133235521 |
oct | 11770655650 |
9 | 3412008204 |
10 | 1340300200 |
11 | 628623418 |
12 | 314a44834 |
13 | 1848a8355 |
14 | ca011848 |
15 | 7ca00eba |
hex | 4fe35ba8 |
1340300200 has 48 divisors (see below), whose sum is σ = 3134291580. Its totient is φ = 533007360.
The previous prime is 1340300191. The next prime is 1340300201. The reversal of 1340300200 is 20030431.
It can be written as a sum of positive squares in 6 ways, for example, as 485673444 + 854626756 = 22038^2 + 29234^2 .
It is a super-2 number, since 2×13403002002 = 3592809252240080000, which contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1340300201) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 15232 + ... + 53968.
Almost surely, 21340300200 is an apocalyptic number.
1340300200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1340300200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1567145790).
1340300200 is an abundant number, since it is smaller than the sum of its proper divisors (1793991380).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1340300200 is a wasteful number, since it uses less digits than its factorization.
1340300200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38926 (or 38917 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 13.
The square root of 1340300200 is about 36610.1106253450. The cubic root of 1340300200 is about 1102.5560943139.
Adding to 1340300200 its reverse (20030431), we get a palindrome (1360330631).
The spelling of 1340300200 in words is "one billion, three hundred forty million, three hundred thousand, two hundred".
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