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1311433 is a prime number
BaseRepresentation
bin101000000001011001001
32110121221121
411000023021
5313431213
644035241
714101264
oct5001311
92417847
101311433
11816332
12532b21
1336bbc6
14261cdb
151ad88d
hex1402c9

1311433 has 2 divisors, whose sum is σ = 1311434. Its totient is φ = 1311432.

The previous prime is 1311419. The next prime is 1311449. The reversal of 1311433 is 3341131.

It is an a-pointer prime, because the next prime (1311449) can be obtained adding 1311433 to its sum of digits (16).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 753424 + 558009 = 868^2 + 747^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311433 - 213 = 1303241 is a prime.

It is not a weakly prime, because it can be changed into another prime (1311403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655716 + 655717.

It is an arithmetic number, because the mean of its divisors is an integer number (655717).

21311433 is an apocalyptic number.

It is an amenable number.

1311433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311433 is an equidigital number, since it uses as much as digits as its factorization.

1311433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 108, while the sum is 16.

The square root of 1311433 is about 1145.1781520794. The cubic root of 1311433 is about 109.4583009493.

Adding to 1311433 its reverse (3341131), we get a palindrome (4652564).

The spelling of 1311433 in words is "one million, three hundred eleven thousand, four hundred thirty-three".