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1311403 is a prime number
BaseRepresentation
bin101000000001010101011
32110121220111
411000022223
5313431103
644035151
714101222
oct5001253
92417814
101311403
11816305
12532ab7
1336bba2
14261cb9
151ad86d
hex1402ab

1311403 has 2 divisors, whose sum is σ = 1311404. Its totient is φ = 1311402.

The previous prime is 1311383. The next prime is 1311407. The reversal of 1311403 is 3041131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1311403 - 29 = 1310891 is a prime.

It is not a weakly prime, because it can be changed into another prime (1311407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655701 + 655702.

It is an arithmetic number, because the mean of its divisors is an integer number (655702).

21311403 is an apocalyptic number.

1311403 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311403 is an equidigital number, since it uses as much as digits as its factorization.

1311403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 1311403 is about 1145.1650536058. The cubic root of 1311403 is about 109.4574662964.

Subtracting from 1311403 its sum of digits (13), we obtain a triangular number (1311390 = T1619).

Adding to 1311403 its reverse (3041131), we get a palindrome (4352534).

The spelling of 1311403 in words is "one million, three hundred eleven thousand, four hundred three".