1213847040 has 320 divisors, whose sum is σ = 4514425344. Its totient is φ = 272498688.

The previous prime is 1213847009. The next prime is 1213847093. The reversal of 1213847040 is 407483121.

It is a tau number, because it is divible by the number of its divisors (320).

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 1213846989 and 1213847007.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3601752 + ... + 3602088.

Almost surely, 2^1213847040 is an apocalyptic number.

1213847040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1213847040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2257212672).

1213847040 is an abundant number, since it is smaller than the sum of its proper divisors (3300578304).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1213847040 is an equidigital number, since it uses as much as digits as its factorization.

1213847040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437 (or 421 counting only the distinct ones).

The product of its (nonzero) digits is 5376, while the sum is 30.

The square root of 1213847040 is about 34840.3076909490. The cubic root of 1213847040 is about 1066.7303573081.

It can be divided in two parts, 1213 and 847040, that added together give a triangular number (848253 = T₁₃₀₂).

The spelling of 1213847040 in words is "one billion, two hundred thirteen million, eight hundred forty-seven thousand, forty".