[go: up one dir, main page]

Search a number
-
+
120132012 = 2237111373137
BaseRepresentation
bin1110010100100…
…01000110101100
322101001100010210
413022101012230
5221223211022
615530502420
72656051050
oct712210654
9271040123
10120132012
11618a1a60
1234294a10
131bb72040
1411d51c60
15a82ea0c
hex72911ac

120132012 has 192 divisors, whose sum is σ = 384297984. Its totient is φ = 28200960.

The previous prime is 120131989. The next prime is 120132017. The reversal of 120132012 is 210231021.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is not an unprimeable number, because it can be changed into a prime (120132017) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 876808 + ... + 876944.

It is an arithmetic number, because the mean of its divisors is an integer number (2001552).

Almost surely, 2120132012 is an apocalyptic number.

120132012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 120132012, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (192148992).

120132012 is an abundant number, since it is smaller than the sum of its proper divisors (264165972).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120132012 is a wasteful number, since it uses less digits than its factorization.

120132012 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 248 (or 246 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 12.

The square root of 120132012 is about 10960.4749897073. The cubic root of 120132012 is about 493.4232205744.

120132012 divided by its sum of digits (12) gives a palindrome (10011001).

Adding to 120132012 its reverse (210231021), we get a palindrome (330363033).

Subtracting 120132012 from its reverse (210231021), we obtain a palindrome (90099009).

The spelling of 120132012 in words is "one hundred twenty million, one hundred thirty-two thousand, twelve".