Base | Representation |
---|---|
bin | 10000110100110… |
… | …00000011100000 |
3 | 100211120020201010 |
4 | 20122120003200 |
5 | 242112211000 |
6 | 22000540520 |
7 | 3332413362 |
oct | 1032300340 |
9 | 324506633 |
10 | 141132000 |
11 | 72735619 |
12 | 3b321740 |
13 | 23315679 |
14 | 14a5ad32 |
15 | c5cbd50 |
hex | 86980e0 |
141132000 has 192 divisors, whose sum is σ = 487468800. Its totient is φ = 35596800.
The previous prime is 141131989. The next prime is 141132007. The reversal of 141132000 is 231141.
It is a happy number.
It is a super-3 number, since 3×1411320003 (a number of 25 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141132007) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 227691 + ... + 228309.
It is an arithmetic number, because the mean of its divisors is an integer number (2538900).
Almost surely, 2141132000 is an apocalyptic number.
141132000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 141132000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (243734400).
141132000 is an abundant number, since it is smaller than the sum of its proper divisors (346336800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141132000 is a wasteful number, since it uses less digits than its factorization.
141132000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 666 (or 648 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 12.
The square root of 141132000 is about 11879.8989894696. The cubic root of 141132000 is about 520.6451558417.
Adding to 141132000 its reverse (231141), we get a palindrome (141363141).
It can be divided in two parts, 1411 and 32000, that added together give a triangular number (33411 = T258).
The spelling of 141132000 in words is "one hundred forty-one million, one hundred thirty-two thousand".
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