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Pomeroy, Iowa

Coordinates: 42°32′54″N 94°41′1″W / 42.54833°N 94.68361°W / 42.54833; -94.68361
From Simple English Wikipedia, the free encyclopedia
Pomeroy, Iowa
Location of Pomeroy, Iowa
Location of Pomeroy, Iowa
Coordinates: 42°32′54″N 94°41′1″W / 42.54833°N 94.68361°W / 42.54833; -94.68361
Country United States
State Iowa
CountyCalhoun
Government
 • TypeMayor-council
Area
 • Total2.05 sq mi (5.30 km2)
 • Land2.05 sq mi (5.30 km2)
 • Water0.00 sq mi (0.00 km2)
Elevation
1,240 ft (378 m)
Population
 • Total526
 • Density256.84/sq mi (99.17/km2)
Time zoneUTC-6 (Central (CST))
 • Summer (DST)UTC-5 (CDT)
ZIP code
50575
Area code712
FIPS code19-64065
GNIS feature ID0460354
WebsiteCity of Pomeroy

Pomeroy is a city in Calhoun County, Iowa, United States. The population of Pomeroy was 526 in 2020.[2]

Pomeroy was hit by a tornado on July 6, 1893, that was estimated to be F5 on the Fujita scale. There was a damage path of around 500 yards (460 m) wide and 55 miles (89 km) long and the tornado destroyed about 80% of the homes in Pomeroy. It killed 71 people and injured 200 others.

References

[change | change source]
  1. "2020 U.S. Gazetteer Files". United States Census Bureau. Retrieved March 16, 2022.
  2. 2.0 2.1 "Pomeroy city, Iowa". United States Census Bureau. Retrieved November 9, 2023.

Other websites

[change | change source]