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a(n) = Sum_{a*b*c=n} omega(a)*omega(b)*mu(c). - Benedict W. J. Irwin, Mar 02 2022
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a(n) = Sum_{a*b*c=n} omega(a)*mu(b)*mu(c). - Benedict W. J. Irwin, Mar 02 2022
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a(n) = Sum_{a*b*c=n} mu(a)*mu(b)*mu(c). - Benedict W. J. Irwin, Mar 02 2022
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a(n) has a lot of overlap with coefficients of [x in expression Table[Sum[Pochhammer[] sum_{k=0}^n x,^(k]FactorialPower[) 1,_(n-k), with [x],{ the coefficient of x, x^(k) the rising factorial, and x_(k,0,n}],{n,0,12}] // Expand // Column) the falling factorial. Benedict W. J. Irwin, Jul 28 2020
In analogy to the first column of the inverse of the lower triangular divisor matrix, A051731, giving the Moebius mu function, A008683, this sequence appears to match (up to sign) the first column of the inverse of the lower triangular matrix where entries are 1 if i and j share a common prime factor, A304569. Benedict W. J. Irwin, Jul 31 2020
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a(n) has a lot of overlap with coefficients of x in expression Table[Sum[Pochhammer[x,k]FactorialPower[1,n-k],{k,0,n}],{n,0,12}] // Expand // Column. Benedict W. J. Irwin, Jul 28 2020
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