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Revisions by Avi Friedlich (See also Avi Friedlich's wiki page)

(Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
Triangle read by rows: T(n,k) = n^2 + n*k + k^2, 1 <= k <= n.
(history; published version)
#48 by Avi Friedlich at Sat Jun 06 21:51:09 EDT 2015
STATUS

editing

proposed

#47 by Avi Friedlich at Sat Jun 06 21:50:40 EDT 2015
COMMENTS

T(n,k) = A093995(n,k) + A075362(n,k) + A133819(n,k) = 2*A070216(n,k) - A215630(n,k), 1 <= k <= n.

The diagonals might derive from 1st subdiagonal T(k+1,k) = A003215(k), the centered hexagonal numbers 3k^2 + 3*k + 1 (A003215). For example, 1st subdiagonal T(k+1,k) = A003215(k). Second subdiagonal T(k+2,k)= A003215(k)/2 + A003215((k+1)/2. Third subdiagonal T(k+3,k) = A003215(k)/3 + A003215((k+1)/3 + A003215(k+2)/3 and so on. - Avi Friedlich, May 26 2015

STATUS

proposed

editing

Discussion
Sat Jun 06
21:51
Avi Friedlich: edited down to reduce size of comment
Expansion of 1/((1-x)(1-x^2)(1-x^3)(1-x^6)).
(history; published version)
#36 by Avi Friedlich at Fri Jun 05 11:23:15 EDT 2015
STATUS

editing

proposed

Discussion
Sat Jun 06
20:42
Avi Friedlich: Comment withdrawn.   Please delete
21:53
Avi Friedlich: Please delete in advance of editorial decision.  On further review, I concur with Drs Arndt and Heinz.
#35 by Avi Friedlich at Fri Jun 05 11:22:32 EDT 2015
COMMENTS

Second differences show expansion of tri-digit zeros interlaced with an arithmetic progression of the natural numbers (A258133). By differentiating coordinates, a(6n-5) = octagonal pyramidal numbers (A002414), a(3*n+1) = second hexagonal numbers (A014105), a(3n) - a(3*n-1) = oblong numbers (A002378), a(3n) + a(3*n-1) = stella octagonal numbers (A007588), and a(3*n+1) - a(3*n-1) = the squares (A000290). - Avi Friedlich, Jun 04 2015

STATUS

proposed

editing

Discussion
Fri Jun 05
11:23
Avi Friedlich: All of it? or just the part I deleted.
#32 by Avi Friedlich at Thu Jun 04 22:55:12 EDT 2015
STATUS

editing

proposed

#31 by Avi Friedlich at Thu Jun 04 22:54:38 EDT 2015
COMMENTS

From: _Second differences show expansion of tri-digit zeros interlaced with an arithmetic progression of the natural numbers (A258133). By differentiating coordinates, a(6n-5) = octagonal pyramidal numbers (A002414), a(3*n+1) = second hexagonal numbers (A014105), a(3n) - a(3*n-1) = oblong numbers (A002378), a(3n) + a(3*n-1) = stella octagonal numbers (A007588), and a(3*n+1) - a(3*n-1) = the squares (A000290). - _Avi Friedlich_, May 11 Jun 04 2015: (Start)

Interlaced formulae may be differentiated to further characterize the sequence. For example: a(6n-5) = octagonal pyramidal numbers: (A002414).

a(3*n+1) = second hexagonal numbers (A014105). a(3n) - a(3*n-1) = oblong numbers (A002378). a(3n) + a(3*n-1) = stella octagonal numbers (A007588). a(3*n+1) - a(3*n-1) = the squares (A000290). First differences reveal triangular numbers a,b,c,d in the order of a, b, b, b, b, c, b, c, c, c, c, d, c, and second differences show expansion of tri-digit zeros interlaced with an arithmetic progression of the natural numbers. (1,0,0,0, 1, -1,1, 0, 0, 0, 2, -2, 2, 0, 0, 0, 3, -3, 3, 0, 0, 0, 4, -4, 4, 0, 0, 0, 5, -5, 5, 0, 0, 0, 6, -6, 6, 0, 0, 0, 7... (A258133). (End)

Spherical growth series for pair of groups, one Gromov hyperbolic, the other not.
(history; published version)
#20 by Avi Friedlich at Tue Jun 02 18:33:03 EDT 2015
STATUS

editing

proposed

#19 by Avi Friedlich at Tue Jun 02 18:32:31 EDT 2015
COMMENTS

In the limit n -> infinity, a(n+1)/a(n) -> 10+6*sqrt(2). - _Avi Friedlich_, Jun 02 2015

Discussion
Tue Jun 02
18:33
Avi Friedlich: thx
#17 by Avi Friedlich at Tue Jun 02 16:12:58 EDT 2015
STATUS

editing

proposed

Discussion
Tue Jun 02
16:38
Robert Israel: Avi: Sign your comment by putting ~~~~ at the end.
#15 by Avi Friedlich at Tue Jun 02 10:49:12 EDT 2015
STATUS

editing

proposed

Discussion
Tue Jun 02
10:55
Michel Marcus: Please, Sign your contribution