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Revision History for A376731 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing all changes.
Expansion of (1 - x^4 - x^5)/((1 - x^4 - x^5)^2 - 4*x^9).
(history; published version)
#10 by Michael De Vlieger at Thu Oct 03 09:57:08 EDT 2024
STATUS

proposed

approved

#9 by Seiichi Manyama at Thu Oct 03 08:39:19 EDT 2024
STATUS

editing

proposed

#8 by Seiichi Manyama at Thu Oct 03 03:36:00 EDT 2024
LINKS

<a href="/index/Rec#order_10">Index entries for linear recurrences with constant coefficients</a>, signature (0,0,0,2,2,0,0,-1,2,-1).

FORMULA

a(n) = 2*a(n-4) + 2*a(n-5) - a(n-8) + 2*a(n-9) - a(n-10).

CROSSREFS
#7 by Seiichi Manyama at Thu Oct 03 01:36:10 EDT 2024
PROG

(PARI) my(N=60, x='x+O('x^N)); Vec((1-x^4-x^5)/((1-x^4-x^5)^2-4*x^9))

#6 by Seiichi Manyama at Thu Oct 03 01:01:33 EDT 2024
FORMULA

a(n) = Sum_{k=0..floor(n/4)} binomial(2*k,2*n-8*k).

#5 by Seiichi Manyama at Thu Oct 03 01:00:26 EDT 2024
CROSSREFS

Cf. A376728.

#4 by Seiichi Manyama at Thu Oct 03 00:57:36 EDT 2024
DATA

1, 0, 0, 0, 1, 1, 0, 0, 1, 6, 1, 0, 1, 15, 15, 1, 1, 28, 70, 28, 2, 45, 210, 210, 46, 67, 495, 924, 496, 157, 1002, 3003, 3004, 1121, 1911, 8009, 12871, 8161, 4880, 18684, 43760, 43948, 23409, 41820, 126124, 184988, 133285, 113373, 324616, 647112, 657273, 454366

PROG

(PARI) a(n) = sum(k=0, n\4, binomial(2*k, 2*n-8*k));

#3 by Seiichi Manyama at Thu Oct 03 00:54:12 EDT 2024
CROSSREFS
#2 by Seiichi Manyama at Thu Oct 03 00:52:54 EDT 2024
NAME

allocated for Seiichi Manyama

Expansion of (1 - x^4 - x^5)/((1 - x^4 - x^5)^2 - 4*x^9).

DATA

1, 0, 0, 0, 1, 1, 0, 0, 1, 6, 1, 0, 1, 15, 15, 1, 1, 28, 70, 28, 2, 45, 210, 210, 46, 67, 495, 924, 496, 157, 1002, 3003

OFFSET

0,10

KEYWORD

allocated

nonn

AUTHOR

Seiichi Manyama, Oct 03 2024

STATUS

approved

editing

#1 by Seiichi Manyama at Thu Oct 03 00:52:54 EDT 2024
NAME

allocated for Seiichi Manyama

KEYWORD

allocated

STATUS

approved