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Revision History for A356711 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
Numbers k such that Mordell's equation y^2 = x^3 + k^3 has exactly 5 integral solutions.
(history; published version)
#16 by Michael De Vlieger at Tue Jun 06 17:40:44 EDT 2023
STATUS

reviewed

approved

#15 by Hugo Pfoertner at Tue Jun 06 17:39:13 EDT 2023
STATUS

proposed

reviewed

#14 by Max Alekseyev at Tue Jun 06 15:01:31 EDT 2023
STATUS

editing

proposed

#13 by Max Alekseyev at Thu Jun 01 17:54:52 EDT 2023
DATA

1, 4, 9, 10, 14, 16, 25, 28, 33, 36, 37, 40, 49, 64, 70, 81, 84, 88, 90, 91, 100, 104, 121, 126, 130, 132, 140, 144, 154, 160, 169, 176, 184, 193, 196

EXTENSIONS

a(31)-a(35) from Max Alekseyev, Jun 01 2023

STATUS

approved

editing

#12 by Michael De Vlieger at Wed Aug 24 12:08:54 EDT 2022
STATUS

proposed

approved

#11 by Jianing Song at Wed Aug 24 12:05:15 EDT 2022
STATUS

editing

proposed

#10 by Jianing Song at Wed Aug 24 12:05:10 EDT 2022
COMMENTS

Contains all six-powerssquares: suppose that y^2 = x^3 + t^6, then (y/t^3)^2 = (x/t^2)^3 + 1. The elliptic curve Y^2 = X^3 + 1 has rank 0 and the only rational points on it are (-1,0), (0,+-1), and (2,+-3), so y^2 = x^3 + t^6 has 5 solutions (-t^2,0), (0,+-t^3), and (2*t^2,+-3*t^3).

#9 by Jianing Song at Wed Aug 24 12:01:34 EDT 2022
COMMENTS

Contains all six-powers: suppose that y^2 = x^3 + t^6, then (y/t^3)^2 = (x/t^2)^3 + 1. The elliptic curve yY^2 = xX^3 - + 1 has rank 0 and the only rational points on it are (-1,0), (0,+-1), and (2,+-3), so y^2 = x^3 + t^6 has 5 solutions (-t^2,0), (0,+-t^3), and (2*t^2,+-3*t^3).

#8 by Jianing Song at Wed Aug 24 11:59:59 EDT 2022
COMMENTS

Contains all six-powers: suppose that y^2 = x^3 + t^6, then (y/t^3)^2 = (x/t^2)^3 + 1. The elliptic curve y^2 = x^3 - 1 has rank 0 and the only rational points on it are (-1,0), (0,+-1), and (2,+-3), so y^2 = x^3 + t^6 has 5 solutions (-t^2,0), (0,+-t^3), and (2*t^2,+-3*t^3).

STATUS

approved

editing

#7 by Michael De Vlieger at Wed Aug 24 09:03:19 EDT 2022
STATUS

proposed

approved