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Main diagonal of A360917.
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a(n) ~ = 2*n^2/3 + O(n) (Beluhov 2023). - Pontus von Brömssen, Jan 30 2023
Nikolai Beluhov, <a href="https://arxiv.org/abs/2301.01152">Snake paths in king and knight graphs</a>, arXiv:2301.01152 [math.CO], 2023.
a(n) ~ 2*n^2/3 + O(n) (Beluhov 2023). - Pontus von Brömssen, Jan 30 2023
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