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a(n) = -4*a(floor(n/4)) + a(n mod 4) for n > 3. (End)
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From Andrey Zabolotskiy, Jan 31 2019: (Start)
a(n) = A073791(2*n)/2.
a(n) = -a(4*n)/4.
a(n) = -4*a(floor(n/4)) + a(n mod 4) for n > 3. (End)
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Andrey Zabolotskiy, <a href="/A320283/b320283_1.txt">Table of n, a(n) for n = 0..8191</a> (terms up to 255 from Andreas K. Badea)
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