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Revision History for A325387 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

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Numbers with adjusted frequency depth 4 whose prime indices cover an initial interval of positive integers.
(history; published version)
#5 by Susanna Cuyler at Thu May 02 16:05:46 EDT 2019
STATUS

proposed

approved

#4 by Gus Wiseman at Thu May 02 15:28:02 EDT 2019
STATUS

editing

proposed

#3 by Gus Wiseman at Thu May 02 13:58:35 EDT 2019
NAME

allocated for Gus WisemanNumbers with adjusted frequency depth 4 whose prime indices cover an initial interval of positive integers.

DATA

12, 18, 24, 48, 54, 72, 96, 108, 144, 162, 192, 288, 324, 360, 384, 432, 486, 540, 576, 600, 648, 720, 768, 864, 972, 1152, 1200, 1260, 1350, 1440, 1458, 1500, 1536, 1620, 1728, 1944, 2100, 2160, 2250, 2304, 2400, 2592, 2880, 2916, 2940, 3072, 3150, 3240, 3456

OFFSET

1,1

COMMENTS

The adjusted frequency depth of a positive integer n is 0 if n = 1, and otherwise it is 1 plus the number of times one must apply A181819 to reach a prime number, where A181819(k = p^i*...*q^j) = prime(i)*...*prime(j) = product of primes indexed by the prime exponents of k. For example, 180 has adjusted frequency depth 5 because we have: 180 -> 18 -> 6 -> 4 -> 3.

The Heinz number of an integer partition (y_1,...,y_k) is prime(y_1)*...*prime(y_k), so these are Heinz numbers of integer partitions with adjusted frequency depth 4 whose parts cover an initial interval of positive integers. The enumeration of these partitions by sum is given by A325335.

EXAMPLE

The sequence of terms together with their prime indices begins:

12: {1,1,2}

18: {1,2,2}

24: {1,1,1,2}

48: {1,1,1,1,2}

54: {1,2,2,2}

72: {1,1,1,2,2}

96: {1,1,1,1,1,2}

108: {1,1,2,2,2}

144: {1,1,1,1,2,2}

162: {1,2,2,2,2}

192: {1,1,1,1,1,1,2}

288: {1,1,1,1,1,2,2}

324: {1,1,2,2,2,2}

360: {1,1,1,2,2,3}

384: {1,1,1,1,1,1,1,2}

432: {1,1,1,1,2,2,2}

486: {1,2,2,2,2,2}

540: {1,1,2,2,2,3}

576: {1,1,1,1,1,1,2,2}

600: {1,1,1,2,3,3}

MATHEMATICA

normQ[n_Integer]:=Or[n==1, PrimePi/@First/@FactorInteger[n]==Range[PrimeNu[n]]];

fdadj[n_Integer]:=If[n==1, 0, Length[NestWhileList[Times@@Prime/@Last/@FactorInteger[#1]&, n, !PrimeQ[#1]&]]];

Select[Range[10000], normQ[#]&&fdadj[#]==4&]

KEYWORD

allocated

nonn

AUTHOR

Gus Wiseman, May 02 2019

STATUS

approved

editing

#2 by Gus Wiseman at Mon Apr 22 07:05:55 EDT 2019
KEYWORD

allocating

allocated

#1 by Gus Wiseman at Mon Apr 22 07:05:55 EDT 2019
NAME

allocated for Gus Wiseman

KEYWORD

allocating

STATUS

approved