The On-Line Encyclopedia of Integer Sequences (OEIS)

Revision History for A262279 (Bold, blue-underlined text is an addition; faded, red-underlined text is a ~~deletion~~.)
Showing entries 1-10 | older changes

A262279

Smallest m such that A261923(m) = n.
(history; published version)

#27 by Joerg Arndt at Thu Sep 21 11:10:13 EDT 2023

STATUS

reviewed

approved

#26 by Michel Marcus at Thu Sep 21 10:49:30 EDT 2023

STATUS

proposed

reviewed

#25 by Michael S. Branicky at Thu Sep 21 10:47:22 EDT 2023

STATUS

editing

proposed

Discussion

Thu Sep 21

10:47

Michael S. Branicky: yes, looks good. sorry for all the small edits.

10:49

Michel Marcus: trop trop fort!!

#24 by Michael S. Branicky at Thu Sep 21 10:47:19 EDT 2023

COMMENTS

a(n) exists for all n. Proof. Let b(i) be the binary representation of i. Let L be its length, and let w = 0^L be a string of L 0's. Then a(n+1) <= u = b(1)wb(2)w...wb(a(n)-1) _2 since u contains the 's binary representation contains that of each number less than a(n) but not that of a(n). So, A261923(u) = 1 + A261923(a(n)). (End)

STATUS

proposed

editing

#23 by Michel Marcus at Thu Sep 21 10:46:47 EDT 2023

STATUS

editing

proposed

Discussion

Thu Sep 21

10:48

Michel Marcus: trop fort !!!

#22 by Michel Marcus at Thu Sep 21 10:46:37 EDT 2023

COMMENTS

a(5) <= 10718873460460617403023221866359404479. - Michael S. Branicky, Sep 21 2023

a(5) <= 10718873460460617403023221866359404479.

STATUS

proposed

editing

Discussion

Thu Sep 21

10:46

Michel Marcus: ok ?

#21 by Michael S. Branicky at Thu Sep 21 10:42:55 EDT 2023

STATUS

editing

proposed

#20 by Michael S. Branicky at Thu Sep 21 10:42:53 EDT 2023

CROSSREFS

Cf. A056744, A261923.

STATUS

proposed

editing

#19 by Michael S. Branicky at Thu Sep 21 10:32:37 EDT 2023

STATUS

editing

proposed

#18 by Michael S. Branicky at Thu Sep 21 10:32:35 EDT 2023

COMMENTS

a(n) exists for all n. Proof. Let b(ni) be the binary representation of ni. Let L be its length, and let w = 0^L be a string of L 0's. Then a(n+1) <= u = b(1)wb(2)w...wb(a(n)-1) since u contains the binary representation of each number less than a(n ) but not that of a(n). So, A261923(u) = 1 + A261923(a(n)). (End)

STATUS

proposed

editing