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Revision History for A260753 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
Least positive integer k such that both k and k*n belong to the set {m>0: prime(prime(m))-prime(m)+1 = prime(p) for some prime p}.
(history; published version)
#20 by N. J. A. Sloane at Tue Aug 18 11:14:59 EDT 2015
STATUS

proposed

approved

#19 by Zhi-Wei Sun at Tue Aug 18 08:23:32 EDT 2015
STATUS

editing

proposed

#18 by Zhi-Wei Sun at Tue Aug 18 08:22:53 EDT 2015
LINKS

Zhi-Wei Sun, <a href="/A260753/a260753.txt">Checking the conjecture for s = -1, t = 1 and r = a/b with (a,b = 1..125)</a>

#17 by Zhi-Wei Sun at Tue Aug 18 08:21:44 EDT 2015
COMMENTS

Conjecture: Any For any s and t in the set {1,-1}, every positive rational number r can be written as m/n with m and n in the set {k>0: prime(prime(k))-+s*prime(k)+1 t = prime(p) for some prime p}.

This conjecture implies that there are infinitely many primes p such that prime(p)-p+1 = prime(q) for some prime q.

We also have some other similar conjecturesIn the case s = -1 and t = 1, the conjecture implies that A261136 has infinitely many terms.

STATUS

proposed

editing

#16 by Zhi-Wei Sun at Tue Aug 18 07:55:56 EDT 2015
STATUS

editing

proposed

#15 by Zhi-Wei Sun at Tue Aug 18 07:55:35 EDT 2015
STATUS

proposed

editing

#14 by Zhi-Wei Sun at Tue Aug 18 07:39:59 EDT 2015
STATUS

editing

proposed

#13 by Zhi-Wei Sun at Tue Aug 18 07:38:52 EDT 2015
COMMENTS

We also have some other similar conjectures.

LINKS

Zhi-Wei Sun, <a href="http://arxiv.org/abs/1402.6641">Problems on combinatorial properties of primes</a>, arXiv:1402.6641 [math.NT], 2014.

Zhi-Wei Sun, <a href="http://arxiv.org/abs/1402.6641">Problems on combinatorial properties of primes</a>, arXiv:1402.6641 [math.NT], 2014.

#12 by Zhi-Wei Sun at Tue Aug 18 07:36:26 EDT 2015
LINKS

Zhi-Wei Sun, <a href="/A260753/a260753.txt">Checking the conjecture for r = a/b with a,b = 1..125</a>

#11 by Zhi-Wei Sun at Tue Aug 18 07:22:28 EDT 2015
EXAMPLE

a(3) = 2279 since prime(prime(2279))-prime(2279)+1 = prime(20147)-20147+1 = 226553-20146 = 206407 = prime(18503) with 18503 prime, and prime(prime(2279*3))-prime(2279*3)+1 = prime(68777)-68777+1 = 865757-68776 = 796981 = prime(63737) with 63737 prime.