The On-Line Encyclopedia of Integer Sequences (OEIS)

Revision History for A259143 (Bold, blue-underlined text is an addition; faded, red-underlined text is a ~~deletion~~.)
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A259143

Number of distinct digits needed to write the calendar date of n-th day of a non-leap year in decimal representation, without leading zeros.
(history; published version)

#13 by Bruno Berselli at Fri May 04 08:11:38 EDT 2018

STATUS

reviewed

approved

#12 by Michel Marcus at Fri May 04 07:21:04 EDT 2018

STATUS

proposed

reviewed

#11 by Halfdan Skjerning at Fri May 04 06:24:32 EDT 2018

STATUS

editing

proposed

#10 by Halfdan Skjerning at Fri May 04 06:22:25 EDT 2018

NAME

Number of distinct digits needed to write the calender calendar date of n-th day of a non-leap year in decimal representation, without leading zeros.

STATUS

reviewed

editing

Discussion

Fri May 04

06:24

Halfdan Skjerning: Thank you too!
I found another typo (one I also tend to make)
Typo in NAME: calender -> calendar

#9 by Michel Marcus at Fri May 04 02:46:30 EDT 2018

STATUS

proposed

reviewed

#8 by Halfdan Skjerning at Fri May 04 02:38:40 EDT 2018

STATUS

editing

proposed

Discussion

Fri May 04

02:46

Michel Marcus: yes thanks

#7 by Halfdan Skjerning at Fri May 04 02:37:43 EDT 2018

EXAMPLE

13 days need just 1 digit: {1, 11, 33, 53, 62, 94, 125, 157, 188, 220, 252, 305, 315} = {Jan 1, Jan 11, Feb 2, Feb 22, Mar 3, Apr 4, Nay May 5, Jun 6, Jul 7, Aug 8, Sep 9, Nov 1, Nov 11};

STATUS

approved

editing

Discussion

Fri May 04

02:38

Halfdan Skjerning: Typo: Nay -> May

#6 by Reinhard Zumkeller at Fri Jun 19 03:18:17 EDT 2015

STATUS

editing

approved

#5 by Reinhard Zumkeller at Fri Jun 19 02:56:43 EDT 2015

COMMENTS

a(n) <= 4.

EXAMPLE

152 days need 2 digits: the first is the 2nd day = Jan 2, the last one is the 356th day = Dec 22;

#4 by Reinhard Zumkeller at Fri Jun 19 01:39:49 EDT 2015

EXAMPLE

. 20 | 3 2 3 3 3 3 3 3 3 3 3 3 . 21 | 2 2 3 3 3 3 3 3 3 3 2 2 . 22 | 2 1 2 2 2 2 2 2 2 3 2 2 . 23 | 3 2 2 3 3 3 3 3 3 4 3 3 . 24 | 3 2 3 2 3 3 3 3 3 4 3 3 . 25 | 3 2 3 3 2 3 3 3 3 4 3 3 . 26 | 3 2 3 3 3 2 3 3 3 4 3 3 . 27 | 3 2 3 3 3 3 2 3 3 4 3 3 . 28 | 3 2 3 3 3 3 3 2 3 4 3 3 . 29 | 3 _ 3 3 3 3 3 3 2 4 3 3 . 30 | 3 _ 2 3 3 3 3 3 3 3 3 4 . 31 | 2 _ 2 _ 3 _ 3 3 _ 3 _ 3 . 13 days need just 1 digit: {1, 11, 33, 53, 62, 94, 125, 157, 188, 220, 252, 305, 315} = {Jan 1, Jan 11, Feb 2, Feb 22, Mar 3, Apr 4, Nay 5, Jun 6, Jul 7, Aug 8, Sep 9, Nov 1, Nov 11}; 152 days need 2 digits: the first is the 2nd day = Jan 2, the last is the 356th day = Dec 22; 192 days need 3 digits: the first is the 20th day = Jan 20, the last one is the last day of the year = Dec 31; 8 days need 4 digits: {296 .. 302, 364} = Oct 23 through Oct 29, and also the penultimate day of the year = Dec 30.

. 20 | 3 2 3 3 3 3 3 3 3 3 3 3

. 21 | 2 2 3 3 3 3 3 3 3 3 2 2

. 22 | 2 1 2 2 2 2 2 2 2 3 2 2

. 23 | 3 2 2 3 3 3 3 3 3 4 3 3

. 24 | 3 2 3 2 3 3 3 3 3 4 3 3

. 25 | 3 2 3 3 2 3 3 3 3 4 3 3

. 26 | 3 2 3 3 3 2 3 3 3 4 3 3

. 27 | 3 2 3 3 3 3 2 3 3 4 3 3

. 28 | 3 2 3 3 3 3 3 2 3 4 3 3

. 29 | 3 _ 3 3 3 3 3 3 2 4 3 3

. 30 | 3 _ 2 3 3 3 3 3 3 3 3 4

. 31 | 2 _ 2 _ 3 _ 3 3 _ 3 _ 3 .

13 days need just 1 digit: {1, 11, 33, 53, 62, 94, 125, 157, 188, 220, 252, 305, 315} = {Jan 1, Jan 11, Feb 2, Feb 22, Mar 3, Apr 4, Nay 5, Jun 6, Jul 7, Aug 8, Sep 9, Nov 1, Nov 11};

152 days need 2 digits: the first is the 2nd day = Jan 2, the last is the 356th day = Dec 22;

192 days need 3 digits: the first is the 20th day = Jan 20, the last one is the last day of the year = Dec 31;

8 days need 4 digits: {296 .. 302, 364} = Oct 23 through Oct 29, and also the penultimate day of the year = Dec 30.