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Revision History for A255250 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
Array T(n, m) of numbers of points of a square lattice in the first octant covered by a circular disk of radius n (centered at any lattice point taken as origin) with ordinate y = m.
(history; published version)
#14 by Michael De Vlieger at Fri May 31 22:04:14 EDT 2024
STATUS

proposed

approved

#13 by Jon E. Schoenfield at Fri May 31 21:35:03 EDT 2024
STATUS

editing

proposed

#12 by Jon E. Schoenfield at Fri May 31 21:35:01 EDT 2024
COMMENTS

This entry is motivated by the proposal A255195 by _Mats Granvik, _, who gave the first differences of this array.

The first octant of a square lattice (x, y) with n = x >= y = m >= 0 is considered. The number of lattice points in this octant covered by a circular disk of radius R = n around the origin having ordinate value y = m are denoted by T(n, m), for n >= 0 and m = 0, 1, ..., floor(n/sqrt(2)).

LINKS

E. W. Weisstein, World of Mathematics, <a href="http://mathworld.wolfram.com/GausssCircleProblem.html">Gauss's Circle Problem </a>.

FORMULA

T(n, m) = floor(sqrt(n^2 - m^2)) - (m-1), n >= 0, m = 0, 1, ..., floor(n/sqrt(2)).

STATUS

approved

editing

#11 by Wolfdieter Lang at Sun Mar 15 12:55:24 EDT 2015
STATUS

editing

approved

#10 by Wolfdieter Lang at Sun Mar 15 12:55:19 EDT 2015
FORMULA

T)m, (n, m) = floor(sqrt(n^2 - m^2)) - (m-1), n >= 0, m = 0,1, ..., floor(n/sqrt(2)).

STATUS

approved

editing

#9 by N. J. A. Sloane at Sun Mar 15 01:45:32 EDT 2015
STATUS

proposed

approved

#8 by Wolfdieter Lang at Sat Mar 14 14:18:18 EDT 2015
STATUS

editing

proposed

#7 by Wolfdieter Lang at Sat Mar 14 14:18:11 EDT 2015
NAME

Array T(n, m) of numbers of points of a square lattice in the first octant covered by a circular disk of radius n (centered at any lattice point taken as origin) with ordinate y = m in the first octant.

COMMENTS

The total number of square lattice points covered in the first quadrant covered by a circular disk of radius R = n is therefore 2*RS(n) - (1 + floor(n/sqrt(2))) = A000603(n).

STATUS

proposed

editing

#6 by Wolfdieter Lang at Sat Mar 14 13:14:53 EDT 2015
STATUS

editing

proposed

#5 by Wolfdieter Lang at Sat Mar 14 13:14:42 EDT 2015
COMMENTS

The total number of square lattice points covered in the first quadrant by a circular disk of radius R = n is therefore 2*RS(n) - (1 + floor(n/sqrt(2))) = A000603(n).

STATUS

proposed

editing