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RealDigits[(360/Pi)*ArcSin[Sqrt[Sin[(Pi/360)^2]]], 10, 120][[1]] (* Harvey P. Dale, Jun 09 2021 *)
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This answers the inverse problem of A231984 (not to be confused with its inverse value): what is the side arc-length of a spherical square required to subtend exactly 1 deg^2. Since the solid angle of a spherical square with side s (in rads) is Omega = 4*arcsin(sin(s/2)^2)) (in sr), we have s = 2*arcsin(sqrt(Omega/4)). Converting Omega = 1 deg^2 into steradians (A231982), applying the formula, and converting the result from radians to degrees (A072097), one obtains the result.
(360/Pi)*arcsin(sqrt(sin((Pi/360)^2))).
(PARI)
default(realprecision, 120);
(360/Pi)*asin(sqrt(sin((Pi/360)^2))) \\ or
(180/Pi)*solve(x = 0, 1, 4*asin(sin(x/2)^2) - (Pi/180)^2) \\ Rick L. Shepherd, Jan 29 2014
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G. V. Brummelen, Heavenly Mathematics: The Forgotten Art of Spherical Trigonometry, Princeton University Press, 2012, ISBN 978-0691148922.
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Wikipedia, <a href="http://en.wikipedia.org/wiki/Solid_angle#Pyramid">Solid angle</a>, Section 3.3 (Pyramid)
Wikipedia, <a href="http://en.wikipedia.org/wiki/Square_degree">Square degree</a>
Wikipedia, <a href="http://en.wikipedia.org/wiki/Steradian">Steradian</a>