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Revision History for A203303 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
Vandermonde determinant of the first n terms of (1,2,4,8,16,...).
(history; published version)
#29 by Joerg Arndt at Fri Sep 01 02:24:13 EDT 2023
STATUS

reviewed

approved

#28 by Michel Marcus at Fri Sep 01 02:21:35 EDT 2023
STATUS

proposed

reviewed

#27 by G. C. Greubel at Thu Aug 31 14:25:57 EDT 2023
STATUS

editing

proposed

#26 by G. C. Greubel at Thu Aug 31 14:25:30 EDT 2023
FORMULA

From Robert Israel, Jan 16 2018: (Start)

a(n) = Product_{0 <= i < j <= n-1} (2^j - 2^i) = 2^(n*(n-1)*(n-2)/6) * Product_{1<=k<=n-1} (2^k-1)^(n-k). - _Robert Israel_, Jan 16 2018

a(n) = 2^(n*(n-1)*(n-2)/6) * Product_{1<=k<=n-1} (2^k-1)^(n-k). (End)

a(n) = Product_{k=0..n-2} ( 2^(k+1)^2 * QPochhammer(2^(-k-1); 2; k+1) ). - G. C. Greubel, Aug 31 2023

MAPLE

# First program

# Second program

MATHEMATICA

(* First program *)

f[j_] := 2^(j - 1); z = 15;

v[n_] := Product[Product[f[k] - f[j], {j, 1, k - 1}], {k, 2, n}]

Table[v[n], {n, 1, z}] (* A203303 *)

Table[v[n + 1]/v[n], {n, 1, z - 1}] (* A002884 *)

Table[v[n] *v[n + 2]/(2*v[n + 1]^2), {n, 1, z - 1}] (* A171499 *)

Table[FactorInteger[v[n]], {n, 1, z - 1}]

(* Second program *)

Table[Product[2^(k+1) -2^j, {k, 0, n-2}, {j, 0, k}], {n, 15}] (* G. C. Greubel, Aug 31 2023 *)

PROG

(Magma) [1] cat [(&*[(&*[2^(k+1) -2^j: j in [0..k]]): k in [0..n-2]]): n in [2..15]]; // G. C. Greubel, Aug 31 2023

(SageMath) [product(product(2^(k+1) -2^j for j in range(k+1)) for k in range(n-1)) for n in range(1, 16)] # G. C. Greubel, Aug 31 2023

CROSSREFS
STATUS

approved

editing

#25 by Vaclav Kotesovec at Tue May 19 11:12:58 EDT 2020
STATUS

editing

approved

#24 by Vaclav Kotesovec at Tue May 19 11:04:37 EDT 2020
FORMULA

a(n) ~ 1/A335011 * 2^(n*(n-1)*(2*n-1)/6) * QPochhammer(1/2)^n. - Vaclav Kotesovec, May 19 2020

STATUS

approved

editing

#23 by Bruno Berselli at Wed Jan 17 04:30:21 EST 2018
STATUS

reviewed

approved

#22 by Joerg Arndt at Wed Jan 17 03:36:25 EST 2018
STATUS

proposed

reviewed

#21 by Robert Israel at Tue Jan 16 21:43:59 EST 2018
STATUS

editing

proposed

#20 by Robert Israel at Tue Jan 16 21:43:51 EST 2018
MAPLE

f:= n -> 2^(n*(n-1)*(n-2)/6)*mul((2^k-1)^(n-k), k=1..n-1):

seq(f(n), n=1..12); # Robert Israel, Jan 16 2018

STATUS

proposed

editing