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a(0) = 1; a(n) = (n-1)! * Sum_{k=1..n} k * 3^floor(k/2)/floor((k+1)/2) * a(n-k)/(n-k)!. - Seiichi Manyama, Apr 30 2022
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Seiichi Manyama, <a href="/A193288/b193288.txt">Table of n, a(n) for n = 0..412</a>
a(0) = 1; a(n) = (n-1)! * Sum_{k=1..n} k * 3^floor(k/2)/floor((k+1)/2) * a(n-k)/(n-k)!. - Seiichi Manyama, Apr 30 2022
(PARI) a_vector(n) = my(v=vector(n+1)); v[1]=1; for(i=1, n, v[i+1]=(i-1)!*sum(j=1, i, j*3^(j\2)/((j+1)\2)*v[i-j+1]/(i-j)!)); v; \\ Seiichi Manyama, Apr 30 2022
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