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All digits are one of the first 10 digits of Phi = A001622, so 2, 4, 5 and 7 never appear. [From _R. J. Mathar (mathar(AT)strw.leidenuniv.nl), _, Mar 14 2009]
More digits from _R. J. Mathar (mathar(AT)strw.leidenuniv.nl), _, Mar 14 2009
1, 3, 6, 8, 1, 8, 8, 8, 8, 8, 9, 0, 8, 8, 8, 0, 8, 0, 8, 1, 1, 0, 3, 8, 3, 8, 8, 0, 8, 3, 3, 3, 8, 8, 6, 6, 9, 9, 1, 1, 8, 1, 8, 6, 9, 8, 8, 1, 3, 9, 3, 1, 8, 3, 1, 6, 8, 3, 0, 0, 8, 3, 1, 1, 9, 1, 3, 1, 3, 1, 0, 3, 1, 8, 6, 8, 8, 1, 1, 0, 0, 8, 9, 1, 9, 1, 1, 9, 1, 1, 0, 6, 8, 8, 8, 8, 6, 6, 8, 9, 0, 8, 0, 9, 3
All digits are one of the first 10 digits of Phi = A001622, so 2, 4, 5 and 7 never appear. [From R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Mar 14 2009]
nonn,base,easy,more,new
More digits from R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Mar 14 2009
Let d(i) be the i-th digit of the decimal expansion of phi=1.6180339887498948482045868...,so that d(0) = 1, d(1) = 6, d(2) = 1, etc. Then a(0) = 1, thereafter a(n) = d(d(n)).
1, 3, 6, 8, 1, 8, 8, 8, 8, 8, 9, 0, 8, 8, 8, 0, 8, 0, 8, 1, 1, 0, 3, 8, 3, 8, 8, 0
0,2
This defines a constant 1.368188888908880808110383880... related to Phi in a peculiar way!
nonn,new,base,easy,more
Dan Brown (ddbhockey(AT)hotmail.com), Feb 21 2009
approved