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Stirling's formula for GAMMAGamma(z) (|arg(z)| < Pi) uses the asymptotic series sum(Sum_{k>=0} (N(k)/a(k))*((1/z)^k)/k!,k=0..infinity). For N(k) see the W. Lang link.
a(n) = denominator(s(n)), where the signed rationals s(n) are the coefficients of ((1/z)^k)/k! in the asymptotic series appearing in Stirling's formula for GAMMAGamma(z).
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W. Lang, <a href="/LANGCHANGE/A097303/a097303.texttxt">More terms and comments</a>.
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W. Lang, <a href="http://www.itp.kit.edu/~wl/EISpubLANGCHANGE
W. Lang, <a href="http://www-.itp.physik.uni-karlsruhekit.deedu/~wl/EISpub/A097303.text">More terms and comments</a>.
max = 15; se = Series[(E^x*Sqrt[1/x]*Gamma[x+1])/(x^x*Sqrt[2*Pi]), {x, Infinity, max}]; Denominator[ CoefficientList[ se /. x -> 1/x, x]*Range[0, max]!] (* From _Jean-François Alcover, _, Nov 03 2011 *)
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Wolfdieter Lang (wolfdieter.lang_AT_physik_DOT_uni-karlsruhe_DOT_de), Aug 13 2004
Wolfdieter Lang, Aug 13 2004
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