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Revision History for A062529 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
Smallest prime p such that there is a gap of 2^n between p and the next prime.
(history; published version)
#43 by N. J. A. Sloane at Sat Jan 28 11:45:50 EST 2023
STATUS

proposed

approved

#42 by Jon E. Schoenfield at Sun Jan 01 20:48:42 EST 2023
STATUS

editing

proposed

#41 by Jon E. Schoenfield at Sun Jan 01 20:48:07 EST 2023
PROG

....while sympy.nextprime(p)-p!=(2**n):

STATUS

proposed

editing

Discussion
Sun Jan 01
20:48
Jon E. Schoenfield: Is it okay to replace the leading dots with spaces in the Python code?
#40 by Sean A. Irvine at Sun Jan 01 17:43:57 EST 2023
STATUS

editing

proposed

#39 by Sean A. Irvine at Sun Jan 01 17:43:45 EST 2023
STATUS

proposed

editing

#38 by Jon E. Schoenfield at Fri Dec 02 19:09:56 EST 2022
STATUS

editing

proposed

Discussion
Wed Dec 14
06:55
Zhining Yang: What else can I do?
Sun Jan 01
17:43
Sean A. Irvine: Are these new additions really the smallest such primes as required by the Name or only the smallest known?
#37 by Jon E. Schoenfield at Fri Dec 02 19:09:54 EST 2022
COMMENTS

a(11) = 5333419265419188034369535864125349, 34 digit, digits, discovered by Helmut Spielauer in 2013

a(12) = 55128448018333565337014555712123010955456071077000028555991469751, 65 digit, digits, discovered by Helmut Spielauer in 2013

a(13) = 192180552346991956641101827551986346298837407139466361414211497406670710665021150917759713696699494356609164354068319457039591759, 129 digit, digits, discovered by Dana Jacobsen in 2016

a(14) = 267552521*631#/210 - 9606, 268 digit, digits, discovered by Dana Jacobsen in 2016

a(15) = 2717*1303#/268590 - 16670, 552 digit, digits, discovered by Dana Jacobsen in 2014

a(16) = 7079*3559#/9870 - 36310, 1517 digit, digits, discovered by Michiel Jansen, Pierre Cami, and Jens Kruse Andersen in 2013

a(17) = 1111111111111111111*9059#/(11#*5237) - 86522, 3899 digit, digits, discovered by Hans Rosenthal in 2017

FORMULA

a(n) = A000230[(2^(n-1)]). - R. J. Mathar, Jan 12 2007

a(n) = A000230[(2^(n-1)] ) = Min{p|nextprime(p)-p = 2^n} [May may need adjusting since offset has been changed].

STATUS

proposed

editing

#36 by Michel Marcus at Fri Dec 02 00:54:47 EST 2022
STATUS

editing

proposed

#35 by Michel Marcus at Fri Dec 02 00:54:41 EST 2022
COMMENTS

From - __Zhining Yang_, Dec 02 2022: (Start)

#34 by Michel Marcus at Fri Dec 02 00:54:23 EST 2022
COMMENTS

Updating:

From - Zhining Yang, Dec 02 2022: (Start)

a(11) to a(17) were searched from Thomas R. Nicely's homepage. (End)

- Zhining Yang, Dec 02 2022.

STATUS

proposed

editing