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Revision History for A003596 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
Numbers of the form 2^i * 11^j.
(history; published version)
#51 by Alois P. Heinz at Fri Nov 03 10:31:38 EDT 2023
STATUS

proposed

approved

#50 by Jon E. Schoenfield at Fri Nov 03 10:30:24 EDT 2023
STATUS

editing

proposed

#49 by Jon E. Schoenfield at Fri Nov 03 10:30:18 EDT 2023
NAME

Numbers of the form 2^i * 11^j.

LINKS

Charles R Greathouse IV, <a href="/A003596/b003596.txt">Table of n, a(n) for n = 1..10000</a> (first 100 terms from Vincenzo Librandi)

STATUS

approved

editing

#48 by N. J. A. Sloane at Sun Oct 22 16:40:31 EDT 2023
STATUS

proposed

approved

#47 by Jon E. Schoenfield at Sun Oct 22 16:25:06 EDT 2023
STATUS

editing

proposed

#46 by Jon E. Schoenfield at Sun Oct 22 16:25:03 EDT 2023
LINKS

Vincenzo Librandi and Charles R Greathouse IV, <a href="/A003596/b003596.txt">Table of n, a(n) for n = 1..10000</a> (first 100 terms from Librandi)

AUTHOR
STATUS

approved

editing

#45 by Charles R Greathouse IV at Thu Sep 08 08:44:32 EDT 2022
PROG

(MAGMAMagma) [n: n in [1..2*10^5] | PrimeDivisors(n) subset [2, 11]]; // Vincenzo Librandi, Jun 27 2016

Discussion
Thu Sep 08
08:44
OEIS Server: https://oeis.org/edit/global/2944
#44 by Joerg Arndt at Wed Sep 23 03:28:14 EDT 2020
STATUS

proposed

approved

#43 by Vaclav Kotesovec at Wed Sep 23 03:28:00 EDT 2020
STATUS

editing

proposed

#42 by Vaclav Kotesovec at Wed Sep 23 03:27:23 EDT 2020
FORMULA

Sum_{n>=1} 1/a(n) = (2*11)/((2-1)*(11-1)) = 11/5. - Amiram Eldar, Sep 23 2020

MATHEMATICA

Sum_{n>=1} 1/a(n) = (2*11)/((2-1)*(11-1)) = 11/5. - Amiram Eldar, Sep 23 2020