OFFSET
1,2
FORMULA
a(n) = Sum_{d|n} 2^(d-1) * binomial(d,n/d-1).
If p is an odd prime, a(p) = 2^(p-1).
MATHEMATICA
a[n_] := DivisorSum[n, 2^(#-1) * Binomial[#, n/# - 1] &]; Array[a, 35] (* Amiram Eldar, Aug 02 2023 *)
PROG
(PARI) my(N=40, x='x+O('x^N)); Vec(sum(k=1, N, (2*x*(1+x^k))^k)/2)
(PARI) a(n) = sumdiv(n, d, 2^(d-1)*binomial(d, n/d-1));
CROSSREFS
KEYWORD
nonn
AUTHOR
Seiichi Manyama, Feb 19 2023
STATUS
approved