A359768 - OEIS

A359768

a(n) = 1 if the parity of n and that of sopfr(n) differ, otherwise 0. Here sopfr is the sum of prime factors (with repetition).

1, 0, 0, 0, 0, 1, 0, 0, 1, 1, 0, 1, 0, 1, 1, 0, 0, 0, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 0, 0, 0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 0, 0, 0, 1, 0, 1, 0, 1, 1, 0, 1, 1, 0, 1, 1, 1, 1, 1, 0, 0, 0, 1, 0, 0, 1, 0, 0, 1, 1, 0, 0, 0, 0, 1, 0, 1, 1, 0, 0, 1, 1, 1, 0, 0, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 1, 1, 0, 0, 1, 1, 0, 1, 1, 0, 1

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OFFSET

LINKS

Antti Karttunen, Table of n, a(n) for n = 1..16384

Index entries for characteristic functions

FORMULA

a(n) = A000035(A075254(n)) = A000035(A075255(n)).

PROG

(PARI)

A001414(n) = ((n=factor(n))[, 1]~*n[, 2]); \\ From A001414.

A359768(n) = ((A001414(n)+n)%2);

(Python)