[go: up one dir, main page]

login

Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 61st year, we have over 378,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).

A251413
a(n) = 2n-1 if n <= 3, otherwise the smallest odd number not occurring earlier having at least one common factor with a(n-2), but none with a(n-1).
3
1, 3, 5, 9, 25, 21, 55, 7, 11, 35, 33, 49, 15, 77, 27, 91, 45, 13, 51, 65, 17, 39, 85, 57, 115, 19, 23, 95, 69, 125, 63, 145, 81, 29, 75, 203, 93, 119, 31, 105, 341, 87, 121, 111, 143, 37, 99, 185, 117, 155, 123, 175, 41, 133
OFFSET
1,2
COMMENTS
Conjecture 1: Sequence is a permutation of the odd numbers.
Conjecture 2: The odd primes occur in the sequence in their natural order.
Comments from N. J. A. Sloane, Dec 13 2014: (Start)
The following properties are known (the proofs are analogous to the proofs for the corresponding facts about A098550).
1. The sequence is infinite.
2. At least one-third of the terms are composite.
3. For any odd prime p, there is a term that is divisible by p.
4. Let a(n_p) be the first term that is divisible by p. Then a(n_p) = q*p where q is an odd prime less than p. If p < r are primes then n_p < n_r.
(End)
REFERENCES
L. Edson Jeffery, Posting to Sequence Fans Mailing List, Dec 01 2014
LINKS
David L. Applegate, Hans Havermann, Bob Selcoe, Vladimir Shevelev, N. J. A. Sloane, and Reinhard Zumkeller, The Yellowstone Permutation, arXiv preprint arXiv:1501.01669, 2015 and J. Int. Seq. 18 (2015) 15.6.7.
MAPLE
N:= 10^3: # to get a(1) to a(n) where a(n+1) is the first term > N
B:= Vector(N, datatype=integer[4]):
for n from 1 to 3 do A[n]:= 2*n-1: od:
for n from 4 do
for k from 4 to N do
if B[k] = 0 and igcd(2*k-1, A[n-1]) = 1 and igcd(2*k-1, A[n-2]) > 1 then
A[n]:= 2*k-1;
B[k]:= 1;
break
fi
od:
if 2*k-1 > N then break fi
od:
seq(A[i], i=1..n-1); # Based on Robert Israel's program for A098550
MATHEMATICA
max = 54; f = True; a = {1, 3, 5}; NN = Range[4, 1000]; s = 2*NN - 1; While[TrueQ[f], For[k = 1, k <= Length[s], k++, If[Length[a] < max, If[GCD[a[[-1]], s[[k]]] == 1 && GCD[a[[-2]], s[[k]]] > 1, a = Append[a, s[[k]]]; s = Delete[s, k]; k = 0; Break], f = False]]]; a (* L. Edson Jeffery, Dec 02 2014 *)
PROG
(Python)
from fractions import gcd
A251413_list, l1, l2, s, b = [1, 3, 5], 5, 3, 7, {}
for _ in range(1, 10**4):
....i = s
....while True:
........if not i in b and gcd(i, l1) == 1 and gcd(i, l2) > 1:
............A251413_list.append(i)
............l2, l1, b[i] = l1, i, True
............while s in b:
................b.pop(s)
................s += 2
............break
........i += 2 # Chai Wah Wu, Dec 07 2014
(Haskell)
import Data.List (delete)
a251413 n = a251413_list !! (n-1)
a251413_list = 1 : 3 : 5 : f 3 5 [7, 9 ..] where
f u v ws = g ws where
g (x:xs) = if gcd x u > 1 && gcd x v == 1
then x : f v x (delete x ws) else g xs
-- Reinhard Zumkeller, Dec 25 2014
CROSSREFS
Sequence in context: A262483 A083366 A006722 * A039774 A114001 A306838
KEYWORD
nonn
AUTHOR
N. J. A. Sloane, Dec 02 2014
STATUS
approved