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Obtuse Triangle


ObtuseTriangle

An obtuse triangle is a triangle in which one of the angles is an obtuse angle. (Obviously, only a single angle in a triangle can be obtuse or it wouldn't be a triangle.) A triangle must be either obtuse, acute, or right.

From the law of cosines, for a triangle with side lengths a, b, and c,

 cosC=(a^2+b^2-c^2)/(2ab),
(1)

with C the angle opposite side C. For an angle to be obtuse, cosC<0. Therefore, an obtuse triangle satisfies one of a^2+b^2<c^2, b^2+c^2<a^2, or c^2+a^2<b^2.

An obtuse triangle can be dissected into no fewer than seven acute triangles (Wells 1986, p. 71).

A famous problem is to find the chance that three points picked randomly in a plane are the polygon vertices of an obtuse triangle (Eisenberg and Sullivan 1996). Unfortunately, the solution of the problem depends on the procedure used to pick the "random" points (Portnoy 1994). In fact, it is impossible to pick random variables which are uniformly distributed in the plane (Eisenberg and Sullivan 1996). Guy (1993) gives a variety of solutions to the problem. Woolhouse (1886) solved the problem by picking uniformly distributed points in the unit disk, and obtained

 P_2=1-(4/(pi^2)-1/8)=9/8-4/(pi^2)=0.719715....
(2)

The problem was generalized by Hall (1982) to n-dimensional ball triangle picking, and Buchta (1986) gave closed form evaluations for Hall's integrals.

ObtuseTriangleArcs

In 1893, Lewis Carroll (1976) posed and gave another solution to the problem as follows. Call the longest side of a triangle AB, and call the diameter 2r. Draw arcs from A and B of radius 2r. Because the longest side of the triangle is defined to be AB, the third polygon vertex of the triangle must lie within the region ABCA. If the third polygon vertex lies within the semicircle, the triangle is an obtuse triangle. If the polygon vertex lies on the semicircle (which will happen with probability 0), the triangle is a right triangle. Otherwise, it is an acute triangle. The chance of obtaining an obtuse triangle is then the ratio of the area of the semicircle to that of ABCA. The area of ABCA is then twice the area of a circular sector minus the area of the triangle.

 A_(whole figure)=2((4pir^2)/6)-sqrt(3)r^2=r^2(4/3pi-sqrt(3)).
(3)

Therefore,

 P=(1/2pir^2)/(r^2(4/3pi-sqrt(3)))=(3pi)/(8pi-6sqrt(3))=0.63938....
(4)

See also

Acute Angle, Acute Triangle, Ball Triangle Picking, Obtuse Angle, Right Triangle, Triangle

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References

Buchta, C. "A Note on the Volume of a Random Polytope in a Tetrahedron." Ill. J. Math. 30, 653-659, 1986.Carroll, L. Pillow Problems & A Tangled Tale. New York: Dover, 1976.Eisenberg, B. and Sullivan, R. "Random Triangles n Dimensions." Amer. Math. Monthly 103, 308-318, 1996.Guy, R. K. "There are Three Times as Many Obtuse-Angled Triangles as There are Acute-Angled Ones." Math. Mag. 66, 175-178, 1993.Hall, G. R. "Acute Triangles in the n-Ball." J. Appl. Prob. 19, 712-715, 1982.Portnoy, S. "A Lewis Carroll Pillow Problem: Probability on at Obtuse Triangle." Statist. Sci. 9, 279-284, 1994.Wells, D. The Penguin Dictionary of Curious and Interesting Numbers. Middlesex, England: Penguin Books, p. 71, 1986.Wells, D. G. The Penguin Book of Interesting Puzzles. London: Penguin Books, pp. 67 and 248-249, 1992.Woolhouse, W. S. B. Solution to Problem 1350. Mathematical Questions, with Their Solutions, from the Educational Times, 1. London: F. Hodgson and Son, 49-51, 1886.

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Obtuse Triangle

Cite this as:

Weisstein, Eric W. "Obtuse Triangle." From MathWorld--A Wolfram Web Resource. https://mathworld.wolfram.com/ObtuseTriangle.html

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