1890 Kansas gubernatorial election
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 County results Humphrey: 30–40% 40–50% 50–60% 60–70% Willits: 30–40% 40–50% 50–60% Robinson: 30–40% 40–50% 50–60% 60–70% | |||||||||||||||||||||
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The 1890 Kansas gubernatorial election was held on November 4, 1890. Incumbent Republican Lyman U. Humphrey defeated People's Party nominee John F. Willits with 39.05% of the vote.
General election
[edit]Candidates
[edit]Major party candidates
- Lyman U. Humphrey, Republican
- Charles L. Robinson, Democratic
Other candidates
- John F. Willits, People's
- A. M. Richardson, Prohibition
Results
[edit]| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | Lyman U. Humphrey (incumbent) | 115,024 | 39.05% | ||
| Populist | John F. Willits | 106,945 | 36.31% | ||
| Democratic | Charles L. Robinson | 71,357 | 24.23% | ||
| Prohibition | A. M. Richardson | 1,230 | 0.42% | ||
| Majority | 8,079 | ||||
| Turnout | |||||
| Republican hold | Swing | ||||
References
[edit]- ^ Guide to U.S. elections - CQ Press, Congressional Quarterly, inc. CQ Press. 2005. ISBN 9781568029818. Retrieved July 5, 2020.