Base | Representation |
---|---|
bin | 1010110010011… |
… | …10010001010011 |
3 | 20022021210002122 |
4 | 11121032101103 |
5 | 141131420011 |
6 | 12551404455 |
7 | 2146135643 |
oct | 531162123 |
9 | 208253078 |
10 | 90498131 |
11 | 470a1649 |
12 | 2638372b |
13 | 159978b9 |
14 | c03a523 |
15 | 7e293db |
hex | 564e453 |
90498131 has 2 divisors, whose sum is σ = 90498132. Its totient is φ = 90498130.
The previous prime is 90498119. The next prime is 90498209. The reversal of 90498131 is 13189409.
It is a weak prime.
It is an emirp because it is prime and its reverse (13189409) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 90498131 - 218 = 90235987 is a prime.
It is a super-2 number, since 2×904981312 = 16379823428986322, which contains 22 as substring.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 90498091 and 90498100.
It is not a weakly prime, because it can be changed into another prime (90498431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 45249065 + 45249066.
It is an arithmetic number, because the mean of its divisors is an integer number (45249066).
Almost surely, 290498131 is an apocalyptic number.
90498131 is a deficient number, since it is larger than the sum of its proper divisors (1).
90498131 is an equidigital number, since it uses as much as digits as its factorization.
90498131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 35.
The square root of 90498131 is about 9513.0505622539. The cubic root of 90498131 is about 448.9657416037.
The spelling of 90498131 in words is "ninety million, four hundred ninety-eight thousand, one hundred thirty-one".
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