Base | Representation |
---|---|
bin | 1010001101001… |
… | …01001110101001 |
3 | 12222002111210211 |
4 | 11012211032221 |
5 | 133404031213 |
6 | 12254541121 |
7 | 2056454005 |
oct | 506451651 |
9 | 188074724 |
10 | 85611433 |
11 | 44364156 |
12 | 248077a1 |
13 | 1497656b |
14 | b527705 |
15 | 77b153d |
hex | 51a53a9 |
85611433 has 2 divisors, whose sum is σ = 85611434. Its totient is φ = 85611432.
The previous prime is 85611373. The next prime is 85611467. The reversal of 85611433 is 33411658.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 66145689 + 19465744 = 8133^2 + 4412^2 .
It is a cyclic number.
It is not a de Polignac number, because 85611433 - 213 = 85603241 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 85611395 and 85611404.
It is not a weakly prime, because it can be changed into another prime (85612433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42805716 + 42805717.
It is an arithmetic number, because the mean of its divisors is an integer number (42805717).
Almost surely, 285611433 is an apocalyptic number.
It is an amenable number.
85611433 is a deficient number, since it is larger than the sum of its proper divisors (1).
85611433 is an equidigital number, since it uses as much as digits as its factorization.
85611433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8640, while the sum is 31.
The square root of 85611433 is about 9252.6446489639. The cubic root of 85611433 is about 440.7347108597.
The spelling of 85611433 in words is "eighty-five million, six hundred eleven thousand, four hundred thirty-three".
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