[go: up one dir, main page]

Search a number
-
+
613050497 is a prime number
BaseRepresentation
bin100100100010100…
…110100010000001
31120201120012011222
4210202212202001
52223420103442
6140455444425
721122562143
oct4442464201
91521505158
10613050497
11295061a04
12151386715
139a017a97
145b5c2c93
1538c498d2
hex248a6881

613050497 has 2 divisors, whose sum is σ = 613050498. Its totient is φ = 613050496.

The previous prime is 613050479. The next prime is 613050551. The reversal of 613050497 is 794050316.

Together with previous prime (613050479) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 484704256 + 128346241 = 22016^2 + 11329^2 .

It is a cyclic number.

It is not a de Polignac number, because 613050497 - 28 = 613050241 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (613050457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 306525248 + 306525249.

It is an arithmetic number, because the mean of its divisors is an integer number (306525249).

Almost surely, 2613050497 is an apocalyptic number.

It is an amenable number.

613050497 is a deficient number, since it is larger than the sum of its proper divisors (1).

613050497 is an equidigital number, since it uses as much as digits as its factorization.

613050497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 22680, while the sum is 35.

The square root of 613050497 is about 24759.8565625894. The cubic root of 613050497 is about 849.5039768040.

The spelling of 613050497 in words is "six hundred thirteen million, fifty thousand, four hundred ninety-seven".