611343407 has 2 divisors, whose sum is σ = 611343408. Its totient is φ = 611343406.

The previous prime is 611343371. The next prime is 611343479. The reversal of 611343407 is 704343116.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 611343407 - 2¹⁴ = 611327023 is a prime.

It is a super-2 number, since 2×611343407² = 747481522564735298, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 611343407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (611363407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 305671703 + 305671704.

It is an arithmetic number, because the mean of its divisors is an integer number (305671704).

Almost surely, 2^611343407 is an apocalyptic number.

611343407 is a deficient number, since it is larger than the sum of its proper divisors (1).

611343407 is an equidigital number, since it uses as much as digits as its factorization.

611343407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 29.

The square root of 611343407 is about 24725.3595929362. The cubic root of 611343407 is about 848.7147390029.

The spelling of 611343407 in words is "six hundred eleven million, three hundred forty-three thousand, four hundred seven".