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65013439 is a prime number
BaseRepresentation
bin1111100000000…
…0011010111111
311112100000200011
43320000122333
5113120412224
610241244051
71416414361
oct370003277
9145300604
1065013439
1133775617
1219933627
1310613bba
1488c4d31
155a93394
hex3e006bf

65013439 has 2 divisors, whose sum is σ = 65013440. Its totient is φ = 65013438.

The previous prime is 65013427. The next prime is 65013449. The reversal of 65013439 is 93431056.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 65013439 - 25 = 65013407 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 65013439.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (65013409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32506719 + 32506720.

It is an arithmetic number, because the mean of its divisors is an integer number (32506720).

Almost surely, 265013439 is an apocalyptic number.

65013439 is a deficient number, since it is larger than the sum of its proper divisors (1).

65013439 is an equidigital number, since it uses as much as digits as its factorization.

65013439 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9720, while the sum is 31.

The square root of 65013439 is about 8063.0911566223. The cubic root of 65013439 is about 402.1002839666.

The spelling of 65013439 in words is "sixty-five million, thirteen thousand, four hundred thirty-nine".