Base | Representation |
---|---|
bin | 1111010110110… |
… | …0101011111001 |
3 | 11111012021121002 |
4 | 3311230223321 |
5 | 112442031223 |
6 | 10220254345 |
7 | 1411314224 |
oct | 365545371 |
9 | 144167532 |
10 | 64408313 |
11 | 333a1a12 |
12 | 196a13b5 |
13 | 10461638 |
14 | 87a85bb |
15 | 59c3e28 |
hex | 3d6caf9 |
64408313 has 2 divisors, whose sum is σ = 64408314. Its totient is φ = 64408312.
The previous prime is 64408277. The next prime is 64408327. The reversal of 64408313 is 31380446.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 36445369 + 27962944 = 6037^2 + 5288^2 .
It is a cyclic number.
It is not a de Polignac number, because 64408313 - 218 = 64146169 is a prime.
It is a Sophie Germain prime.
It is a Chen prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (64408343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32204156 + 32204157.
It is an arithmetic number, because the mean of its divisors is an integer number (32204157).
Almost surely, 264408313 is an apocalyptic number.
It is an amenable number.
64408313 is a deficient number, since it is larger than the sum of its proper divisors (1).
64408313 is an equidigital number, since it uses as much as digits as its factorization.
64408313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 29.
The square root of 64408313 is about 8025.4789888205. The cubic root of 64408313 is about 400.8488494456.
Adding to 64408313 its reverse (31380446), we get a palindrome (95788759).
The spelling of 64408313 in words is "sixty-four million, four hundred eight thousand, three hundred thirteen".
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