Base | Representation |
---|---|
bin | 1011111101011010… |
… | …10010000110001001 |
3 | 121120110210202122101 |
4 | 11332231102012021 |
5 | 101122204021423 |
6 | 2541043153401 |
7 | 315053422435 |
oct | 57655220611 |
9 | 17513722571 |
10 | 6420767113 |
11 | 27a53a0402 |
12 | 12b2375861 |
13 | 7b42cb9a7 |
14 | 44ca5b9c5 |
15 | 278a4e7ad |
hex | 17eb52189 |
6420767113 has 2 divisors, whose sum is σ = 6420767114. Its totient is φ = 6420767112.
The previous prime is 6420767047. The next prime is 6420767117. The reversal of 6420767113 is 3117670246.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5024399689 + 1396367424 = 70883^2 + 37368^2 .
It is a cyclic number.
It is not a de Polignac number, because 6420767113 - 213 = 6420758921 is a prime.
It is not a weakly prime, because it can be changed into another prime (6420767117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3210383556 + 3210383557.
It is an arithmetic number, because the mean of its divisors is an integer number (3210383557).
Almost surely, 26420767113 is an apocalyptic number.
It is an amenable number.
6420767113 is a deficient number, since it is larger than the sum of its proper divisors (1).
6420767113 is an equidigital number, since it uses as much as digits as its factorization.
6420767113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 42336, while the sum is 37.
The square root of 6420767113 is about 80129.6893354766. The cubic root of 6420767113 is about 1858.6415402651.
The spelling of 6420767113 in words is "six billion, four hundred twenty million, seven hundred sixty-seven thousand, one hundred thirteen".
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