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53952047 is a prime number
BaseRepresentation
bin1100110111001…
…1111000101111
310202112001021222
43031303320233
5102302431142
65204213555
71223404412
oct315637057
9122461258
1053952047
11284aaa76
121609a2bb
13b2401b6
147245b79
154b0abd2
hex3373e2f

53952047 has 2 divisors, whose sum is σ = 53952048. Its totient is φ = 53952046.

The previous prime is 53952029. The next prime is 53952053. The reversal of 53952047 is 74025935.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 53952047 - 26 = 53951983 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 53951998 and 53952016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53952247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26976023 + 26976024.

It is an arithmetic number, because the mean of its divisors is an integer number (26976024).

Almost surely, 253952047 is an apocalyptic number.

53952047 is a deficient number, since it is larger than the sum of its proper divisors (1).

53952047 is an equidigital number, since it uses as much as digits as its factorization.

53952047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 37800, while the sum is 35.

The square root of 53952047 is about 7345.2057152948. The cubic root of 53952047 is about 377.8643985115.

The spelling of 53952047 in words is "fifty-three million, nine hundred fifty-two thousand, forty-seven".