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5355525133 = 7765075019
BaseRepresentation
bin1001111110011011…
…01101010000001101
3111211020100212100201
410333031231100031
541432003301013
62243231253501
7246500132620
oct47715552015
914736325321
105355525133
1122a9066332
12105567a291
136746ca8aa
1438b3a9db7
152152823dd
hex13f36d40d

5355525133 has 4 divisors (see below), whose sum is σ = 6120600160. Its totient is φ = 4590450108.

The previous prime is 5355525107. The next prime is 5355525139. The reversal of 5355525133 is 3315255535.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5355525133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5355525092 and 5355525101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5355525139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 382537503 + ... + 382537516.

It is an arithmetic number, because the mean of its divisors is an integer number (1530150040).

Almost surely, 25355525133 is an apocalyptic number.

It is an amenable number.

5355525133 is a deficient number, since it is larger than the sum of its proper divisors (765075027).

5355525133 is an equidigital number, since it uses as much as digits as its factorization.

5355525133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 765075026.

The product of its digits is 168750, while the sum is 37.

The square root of 5355525133 is about 73181.4534769569. The cubic root of 5355525133 is about 1749.5808664806.

The spelling of 5355525133 in words is "five billion, three hundred fifty-five million, five hundred twenty-five thousand, one hundred thirty-three".

Divisors: 1 7 765075019 5355525133