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5335147 = 17330839
BaseRepresentation
bin10100010110100001101011
3101001001110001
4110112201223
52331211042
6310203431
763230236
oct24264153
911031401
105335147
113014414
121953577
13114a4bc
149cc41d
15705bb7
hex51686b

5335147 has 4 divisors (see below), whose sum is σ = 5366160. Its totient is φ = 5304136.

The previous prime is 5335133. The next prime is 5335151. The reversal of 5335147 is 7415335.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5335147 - 215 = 5302379 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5335117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15247 + ... + 15592.

It is an arithmetic number, because the mean of its divisors is an integer number (1341540).

Almost surely, 25335147 is an apocalyptic number.

5335147 is a deficient number, since it is larger than the sum of its proper divisors (31013).

5335147 is a wasteful number, since it uses less digits than its factorization.

5335147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31012.

The product of its digits is 6300, while the sum is 28.

The square root of 5335147 is about 2309.7937137329. The cubic root of 5335147 is about 174.7358954998.

The spelling of 5335147 in words is "five million, three hundred thirty-five thousand, one hundred forty-seven".

Divisors: 1 173 30839 5335147