53131433 has 2 divisors, whose sum is σ = 53131434. Its totient is φ = 53131432.

The previous prime is 53131423. The next prime is 53131453. The reversal of 53131433 is 33413135.

It is a happy number.

53131433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 30824704 + 22306729 = 5552^2 + 4723^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-53131433 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 53131399 and 53131408.

It is not a weakly prime, because it can be changed into another prime (53131423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26565716 + 26565717.

It is an arithmetic number, because the mean of its divisors is an integer number (26565717).

Almost surely, 2^53131433 is an apocalyptic number.

It is an amenable number.

53131433 is a deficient number, since it is larger than the sum of its proper divisors (1).

53131433 is an equidigital number, since it uses as much as digits as its factorization.

53131433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1620, while the sum is 23.

The square root of 53131433 is about 7289.1311553573. The cubic root of 53131433 is about 375.9388221915.

Adding to 53131433 its reverse (33413135), we get a palindrome (86544568).

The spelling of 53131433 in words is "fifty-three million, one hundred thirty-one thousand, four hundred thirty-three".