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5311310413 is a prime number
BaseRepresentation
bin1001111001001010…
…00010101001001101
3111201011011112011111
410330211002221031
541334143413123
62235011452021
7245422252003
oct47445025115
914634145144
105311310413
112286107142
1210428b7011
136684b9836
1438557aa73
1521144b90d
hex13c942a4d

5311310413 has 2 divisors, whose sum is σ = 5311310414. Its totient is φ = 5311310412.

The previous prime is 5311310339. The next prime is 5311310429. The reversal of 5311310413 is 3140131135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3296826724 + 2014483689 = 57418^2 + 44883^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5311310413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5311310113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2655655206 + 2655655207.

It is an arithmetic number, because the mean of its divisors is an integer number (2655655207).

Almost surely, 25311310413 is an apocalyptic number.

It is an amenable number.

5311310413 is a deficient number, since it is larger than the sum of its proper divisors (1).

5311310413 is an equidigital number, since it uses as much as digits as its factorization.

5311310413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 22.

The square root of 5311310413 is about 72878.7377291896. The cubic root of 5311310413 is about 1744.7527626231.

Adding to 5311310413 its reverse (3140131135), we get a palindrome (8451441548).

The spelling of 5311310413 in words is "five billion, three hundred eleven million, three hundred ten thousand, four hundred thirteen".